Step: 1
Here
f(
x) = cos (sin
x) is a differential function in (0,
π2)
[Given function.]
Step: 2
f ′ (
x) =
ddxcos (sin
x)
[Differentiate.]
Step: 3
= - sin (sin x) ddx (sin x)
Step: 4
Step: 5
For x ∈ (0, π2), sinx ∈ (0, 1) and cos x ∈ (0, 1)
Step: 6
=> sin (sin x) > 0 and cos x > 0
Step: 7
⇒ sin (sin x) cos x > 0
Step: 8
⇒ - sin (sin x) cos x < 0
Step: 9
So f ′ (x) < 0 for x ∈ (0, π2)
Step: 10
So in (0, π2), f(x) is decreasing.
Correct Answer is : decreasing