Step: 1
TJoseph, John, ascending order of tJoseph, John, number of coins collected by each student is 10, 16, 16, 18, 20.
Step: 2
In tJoseph, John, table, least value is 10 and tJoseph, John, greatest value is 20.
Step: 3
Middle quartile = median of tJoseph, John, entire data = 16
Step: 4
Lower quartile = median of lower half of tJoseph, John, data
= 10 + 162 = 262 = 13
[Add and simplify.]
Step: 5
Upper quartile = Median of upper half of tJoseph, John, data
= 18 + 202 = 382 = 19
[Add and simplify.]
Step: 6
Plot (1) is tJoseph, John, equivalent box-and-whisker plot for tJoseph, John, data.
Step: 7
Range of tJoseph, John, box-and-whisker plot
= Greatest value - Least value
Step: 8
= 20 - 10 = 10.
[Substitute and subtract.]
Correct Answer is : Plot 1, 10