y3 = x3 + 1

y = x + 3

Choose values for x.

Plot the points on a graph.

The above graph matches with the Graph 3.

So, Graph 3 represents the equation.

Calculate the values of y for some values of x as shown in the following table.

Plot the points on the graph

So, Graph 2 represents the equation y = - x + 2.

y = - x - 3

Choose values for x.

Plot the points on a graph.

The above graph matches with the graph in choice B.

So, choice B is the correct answer.

y = 1x

y = 1(- 2) = - 2

y = 1(- 1) = - 1

y = 1(0) = 0

y = 1(1) = 1

y = 1(2) = 2

Plot the graph for the above values of x and y.

Among the graphs, Graph 1 suits the equation.

y = 100 x

At x = 0, y = 100(0) = 0

At x = 1, y = 100(1) = 100

At x = 2, y = 100(2) = 200

At x = 3, y = 100(3) = 300

Represent the above data in tabular form, as shown below.

Among the choices, Graph 2 suits the result.

The x-coordinate is always - 8, regardless of the value of y.

The graph of the equation x = - 8 is a vertical line 8 units to the left of the y-axis as shown in the following graph.

The above graph matches with the graph 3.

Solve the equation for y.
- 2x +y = 1 →y = 2x + 1

Calculate the values of y for some values of x as shown in the following table.

Plot the points on the graph.

So, Graph 4 represents the equation - 2x +y = 1.

x + 2y = 6

Solve the equation for y.
x + 2y = 6→ y = - x2 + 3

Calculate the values of y for some values of x as shown in the following table.

Plot the points and draw the line by joining them.

Therefore Graph 4 represents the equation x + 2y = 6. .

Solve the equation for y.
- x- y = - 2 →- y = x - 2

Choose values for x.

Plot the points on a graph.

The above graph matches with the Graph 2.

From the equation y = (32)x + 1, y-intercept is 1 and the slope is 32.

Plot the point (0, 1).

Move 3 units up from the point (0, 1). Then move 2 units right to plot the second point. Repeat the pattern to plot more points.

Draw a line passing through these points.

The above graph matches with Graph 4.